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Re: Darcy / Colebrook-White Equations
regarding your formula:
f = 1/ [ 4 * log10((e/3.7D) + ((2.51/Re*sqrt(f))))]^2
it seems be incorrect. my transformation was:
(1/sqrt(f))^2=(-2log10((e/3.7D) + ((2.51/Re*sqrt(f)))))^2 <=>
1/f=[-2 * log10((e/3.7D) + ((2.51/Re*sqrt(f))))]^2 <=>
f=1/[-2 * log10((e/3.7D) + ((2.51/Re*sqrt(f))))]^2 or
f = 1/ 4 *[ log10((e/3.7D) + ((2.51/Re*sqrt(f))))]^2
if i'm wrong, please correct me, it's been a while since i worked with these formulas. The solving method you've proposed works with these formulas. There's however another way to solve this, using the Goalseek tool in Microsoft Excel. The way i do it is:
first i transform the colebrook formula in:
1=-2*sqrt((f))*log10((e/3.7D) + ((2.51/Re*sqrt(f))))
then, in cell A, i write the formula
=-2*sqrt((f))*log10((e/3.7D) + ((2.51/Re*sqrt(f))))
and in cell B i put a starting number for f
then, with goalseek, make excel calculate the formula in A to value 1 by changing the B cell
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